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24/25 EHE - The quadratic formula
thomas.payne
Created on March 6, 2024
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Transcript
20
AS
The Quadratic Formula
y dπ₯
A = lw
b2-4ac
Challenge
1. 5 - 8 Γ 22. 0.55 + 0.65 3. 34 Γ 32 = 4. Find 35% of 80 5. 2, 2, 3, 4, 6, 2, 5, 5, 5, 2 [Mode] 6. What is Ο? 7. A sequence goes 3, 7, 11, 15, 19,.. nth term? 8. The exterior angles for any shape add up to?
Quizizz - 8Qs21
AS
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Pin: 6272 0620
y dπ₯
A = lw
b2-4ac
But what happens when you can't factorise?
Some quadratic equations (got x2) can be solved by factorising. Like this one.
Solve x2 + 5x + 6 = 0
AS
The Quadratic Formula
y dπ₯
A = lw
b2-4ac
AS
y dπ₯
The quadratic formula
A = lw
b2-4ac
AS
y dπ₯
The quadratic formula
A = lw
b2-4ac
AS
Write what A, B and C would be for each
1) x2 + 14x + 24 = 0 2) x2 + 9x + 18 = 0 3) x2 -7x + 12 = 0 4) 2x2 -10x - 21 = 0 5) 3x2 - 4x + 2 = 0 6) x2 + 2 -4x = 0 7) 1 + 2x -4x2 = 0 8) 1/3 + 2x - 0.4x2 = 0
y dπ₯
The quadratic formula
A = lw
b2-4ac
AS
The quadratic formula
y dπ₯
A = lw
b2-4ac
AS
The quadratic formula
y dπ₯
A = lw
b2-4ac
Solve: 1) π₯2 - 2π₯ - 3 = 0 2) π₯2 - 6π₯ - 55 = 0 3) 2π₯2 + 4π₯ - 390 = 0 4) 5π₯2 - 50π₯ - 595 = 0 5) π₯2 - 7π₯ - 15 = 0 6) 3π₯2 - 34π₯ + 82 = 0
AS
The quadratic formula
y dπ₯
A = lw
b2-4ac
AS
y dπ₯
The quadratic formula
A = lw
b2-4ac
Solve: 1) 2π₯2 + 4π₯ = 7 2) 7 = 13π₯ + 5π₯2 3) 22π₯2 = 6 + 15π₯
AS
The quadratic formula
y dπ₯
A = lw
b2-4ac
AS
The quadratic formula
y dπ₯
A = lw
b2-4ac
AS
The quadratic formula
y dπ₯
A = lw
b2-4ac
2)
3)
1)
AS
The quadratic formula
y dπ₯
A = lw
b2-4ac
https://drive.google.com/file/d/1cw-5LkBKjywGEAnNUU7bDLDsUHd4x1ia/view?usp=sharing
AS
Simultanous equations
y dπ₯
A = lw
b2-4ac
AS
y dπ₯
Past paper questions
A = lw
b2-4ac
AS
y dπ₯
A = lw
b2-4ac
https://drive.google.com/file/d/1cw-5LkBKjywGEAnNUU7bDLDsUHd4x1ia/view?usp=sharing
AS
y dπ₯
A = lw
b2-4ac
https://drive.google.com/file/d/1cw-5LkBKjywGEAnNUU7bDLDsUHd4x1ia/view?usp=sharing
AS
y dπ₯
A = lw
b2-4ac
https://drive.google.com/file/d/1cw-5LkBKjywGEAnNUU7bDLDsUHd4x1ia/view?usp=sharing
AS
y dπ₯
A = lw
b2-4ac
y dπ₯
Logs
dx
dy
f(π₯+a)
b2-4ac
y dπ₯
Logs
dx
dy
f(π₯+a)
b2-4ac
Foundation
Higher
A Level
y dπ₯
Logs
dx
dy
f(π₯+a)
b2-4ac
Foundation
Higher
A Level
Foundation
Higher
A Level
y dπ₯
Logs
dx
dy
f(π₯+a)
b2-4ac
Foundation
Higher
A Level
Foundation
Higher
A Level
Foundation
Higher
A Level
Foundation
Higher
A Level
y dπ₯
Logs
dx
dy
f(π₯+a)
b2-4ac
Foundation
Higher
A Level
y dπ₯
Logs
dx
dy
f(π₯+a)
b2-4ac
y dπ₯
Logs
dx
dy
f(π₯+a)
b2-4ac
Foundation
Higher
A Level
Foundation
Higher
A Level
y dπ₯
Logs
dx
dy
f(π₯+a)
b2-4ac
Foundation
Higher
A Level
y dπ₯
Logs
dx
dy
f(π₯+a)
b2-4ac
y dπ₯
Logs
dx
dy
f(π₯+a)
b2-4ac
Foundation
Higher
A Level
Foundation
Higher
A Level
Foundation
Higher
A Level
Foundation
Higher
A Level
Foundation
Higher
A Level
Foundation
Higher
A Level
Foundation
Higher
A Level
y dπ₯
Logs
dx
dy
f(π₯+a)
b2-4ac
y dπ₯
Logs
dx
dy
f(π₯+a)
b2-4ac
y dπ₯
Logs
dx
dy
f(π₯+a)
b2-4ac
y dπ₯
Logs
dx
dy
f(π₯+a)
b2-4ac
y dπ₯
Logs
dx
dy
f(π₯+a)
b2-4ac
Foundation
Higher
A Level
y dπ₯
Logs
dx
dy
f(π₯+a)
b2-4ac
y dπ₯
Logs
dx
dy
f(π₯+a)
b2-4ac
y dπ₯
Logs
dx
dy
f(π₯+a)
b2-4ac
y dπ₯
Logs
dx
dy
f(π₯+a)
b2-4ac
Foundation
Higher
A Level