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24/25 EHE - Vectors
thomas.payne
Created on January 17, 2024
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Vectors
y dπ₯
b2-4ac
A = lw
AS
Quizizz - 8Qs32
Pin: 2640 1968
Challenge
joinmyquiz.com
1. Solve 2π₯ + 1 = 262. Simplify fully 3 : 12 : 21 3. Write 0.08 as a percentage. 4. Convert 1.3L into ml 5. Evaluate 4g5p3 Γ· 2g2p 6. Order, smallest to biggest: 0.12 15% 0.012 10% 7. Write the formula for the area of a trapezium. 8. Is 2π₯ + 1 = 26 an expression/identity/equation/formula
y dπ₯
b2-4ac
A = lw
AS
VEctors
y dπ₯
b2-4ac
A = lw
AS
VEctors
y dπ₯
b2-4ac
A = lw
AS
VEctors
Describe these as column vectors
y dπ₯
b2-4ac
A = lw
AS
VEctors
y dπ₯
b2-4ac
A = lw
AS
VEctors
y dπ₯
b2-4ac
A = lw
AS
VEctors
y dπ₯
b2-4ac
A = lw
AS
VEctors
y dπ₯
b2-4ac
A = lw
AS
VEctors
y dπ₯
b2-4ac
A = lw
AS
Vectors
y dπ₯
Century Tasks
b2-4ac
01
Column Vectors [MF41.01]
A = lw
Column Vectors: Scalar Multiplication [MF41.02]
02
Head to 'my courses'
Click on this one
Then search for the nugget.
Column Vectors: Addition and Subtraction [MF41.03]
03
Geometric Vectors 1: One Term [MF41.05]
AS
04
Geometric Vectors 2: Two Terms [MF41.06]
05
https://drive.google.com/file/d/1cw-5LkBKjywGEAnNUU7bDLDsUHd4x1ia/view?usp=sharing
Past paper questions
y dπ₯
b2-4ac
A = lw
AS
Past paper questions
y dπ₯
b2-4ac
A = lw
AS
Past paper questions
y dπ₯
b2-4ac
A = lw
AS
y dπ₯
b2-4ac
A = lw
AS
y dπ₯
b2-4ac
A = lw
AS
https://drive.google.com/file/d/1cw-5LkBKjywGEAnNUU7bDLDsUHd4x1ia/view?usp=sharing
y dπ₯
b2-4ac
A = lw
AS
https://drive.google.com/file/d/1cw-5LkBKjywGEAnNUU7bDLDsUHd4x1ia/view?usp=sharing
y dπ₯
b2-4ac
A = lw
AS
https://drive.google.com/file/d/1cw-5LkBKjywGEAnNUU7bDLDsUHd4x1ia/view?usp=sharing
b2-4ac
dy
dx
f(π₯+a)
y dπ₯
Logs
A Level
Higher
Foundation
A Level
Higher
Foundation
A Level
Higher
Foundation
A Level
Higher
Foundation
A Level
Higher
Foundation
A Level
Higher
Foundation
A Level
Higher
Foundation
b2-4ac
dy
dx
f(π₯+a)
y dπ₯
Logs
b2-4ac
dy
dx
f(π₯+a)
y dπ₯
Logs
A Level
Higher
Foundation
A Level
Higher
Foundation
A Level
Higher
Foundation
Work out 13 Γ· 0.3Β²
b2-4ac
dy
dx
f(π₯+a)
y dπ₯
Logs
b2-4ac
dy
dx
f(π₯+a)
y dπ₯
Logs
A Level
Higher
Foundation
A Level
Higher
Foundation
b2-4ac
dy
dx
f(π₯+a)
y dπ₯
Logs
A Level
Higher
Foundation
b2-4ac
dy
dx
f(π₯+a)
y dπ₯
Logs
b2-4ac
dy
dx
f(π₯+a)
y dπ₯
Logs
b2-4ac
dy
dx
f(π₯+a)
y dπ₯
Logs
A Level
Higher
Foundation
b2-4ac
dy
dx
f(π₯+a)
y dπ₯
Logs
b2-4ac
dy
dx
f(π₯+a)
y dπ₯
Logs
A Level
Higher
Foundation
A Level
Higher
Foundation
b2-4ac
dy
dx
f(π₯+a)
y dπ₯
Logs
b2-4ac
dy
dx
f(π₯+a)
y dπ₯
Logs
b2-4ac
dy
dx
f(π₯+a)
y dπ₯
Logs
A Level
Higher
Foundation
b2-4ac
dy
dx
f(π₯+a)
y dπ₯
Logs
b2-4ac
dy
dx
f(π₯+a)
y dπ₯
Logs
b2-4ac
dy
dx
f(π₯+a)
y dπ₯
Logs
A Level
Higher
Foundation