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Avogadro's Army - Operation: Decorate the Christmas Tree!

Elise Welfare

Created on November 4, 2025

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Transcript

Operation: Decorate the Christmas Tree!

Begin your journey through four festive missions, Balls, Stars, Lights, and Ribbons, each filled with Christmas-themed chemistry puzzles that test your wit and holiday spirit. Complete all missions to earn the magical ornaments needed to decorate the tree and restore Christmas cheer to the North Pole!

Start

Missions

4. Ribbons

1. Balls

2. Stars

3. Lights

Question 1/3

Correct!

Convert molecules to moles using Avogadro’s number: moles = particles ÷ (6.022 x 10^23) (3.00 x 10^23) ÷ (6.022 x 10^23) = 0.199… ≈ 0.200 mol

Next

Question 2/3

Correct!

Step 1: Add candy per stocking12.50 + 7.2 = 19.7 g (1 decimal place) Step 2: Multiply by 9 19.7 × 9 = 177.3 → 3 sig figs → 177 g

next

Question 3/3

Correct!

next

Convert the mass of AgCl to moles using its molar mass. Use the 2:1 ratio from the balanced equation to find moles of 𝑀𝐶𝑙2 (divide moles of AgCl by 2). Find the molar mass of 𝑀𝐶𝑙2 by dividing the sample mass by the moles of 𝑀𝐶𝑙2 Subtract the mass of two Cl atoms from 𝑀𝐶𝑙2 to get the atomic mass of 𝑀 Match that mass to the periodic table → the value corresponds to Fe, so Fe is the answer.

Incorrect! You receive coal.

Back

Gifts for decorating!

Follow

Missions

4. Ribbons

1. Balls

2. Stars

3. Lights

Question 1/3

Correct!

Volume displaced = 28.5 mL – 22.0 mL = 6.5 mLDensity = mass ÷ volume = 48.6 g ÷ 6.5 mL = 1.82 g/mL

next

Question 2/3

Correct!

Convert % to grams → to moles → then simplify the ratio: C: 52.2 g ÷ 12.01 ≈ 4.35 mol H: 13.1 g ÷ 1.008 ≈ 13.0 mol O: 34.7 g ÷ 16.00 ≈ 2.17 mol Divide all by the smallest (2.17): C: 4.35 ÷ 2.17 ≈ 2 H: 13.0 ÷ 2.17 ≈ 6 O: 2.17 ÷ 2.17 ≈ 1 → C₂H₆O

Follow

Question 3/3

Correct!

Lattice energy increases with small ions + high charge. Li⁺ and F⁻ are the smallest ions listed.

Follow

Incorrect!

List of naughty children

Back

Gifts for decorating!

Follow

Missions

4. Ribbons

1. Balls

2. Stars

3. Lights

Question 1/3

Correct!

Ammonium = NH₄⁺ and carbonate = CO₃²⁻ → need 2 ammonium ions: (NH₄)₂CO₃

next

Question 2/3

Correct!

Cl is –1. Three Cl⁻ = –3 total, so Fe must be +3

next

Question 3/3

Correct!

Melting ice is an endothermic process, which means it absorbs heat from the surroundings, so the enthalpy of the ice increases as it turns into liquid water.

next

Incorrect! You lose gifts.

Back

Gifts for decoration!

Follow

Missions

4. Ribbons

1. Balls

2. Stars

3. Lights

Question 1/3

Correct!

next

Al-O is the least polar because the shared electron pair is not strongly pulled to oxygen. This means there is only a small difference in charge and thus the bond is not very polar. Mg-O has moderate polarity because they have a stronger dipole than Al-O but still not the largest separation of charges. Na-O represents the most ionic bond and thus has the largest charge separation. Therefore, Na-O is the most polar bond represented

Question 2/3

Correct!

Neon is a noble gas, nonpolar, with almost no intermolecular forces. This is ideal gas behavior at STP.

next

Question 3/3

Correct!

N₂H₄: 2x +4(+1) = 0 so x = -2 NO: x + (-2) = 0 so x = +2 HNO₃: (+1) + x + 3(-2) = 0 so x = +5

next

Incorrect! Fireplace is on.

Back

Gifts for decorating!

Follow

Missions

4. Ribbons

1. Balls

2. Stars

3. Lights

Decorate

Merry Christmas!

Do you want to exit without decorating your Christmas tree?

Exit

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