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Solving Systems of Linear Equations

Kosten Edwards [STUDENT]

Created on October 28, 2025

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Solving Systems of Linear Equations

y+2x=2->y=-2x+2 y+2x=-2 Lines are parallel->y=-2x-2 No solution

Substitute y=-2x+2 into y+2x=-2(-2x+2)+2x=-2Simplify: -2x+2+2x=-22=-2The statement 2=-2 is false meaning there is no solution

y+2x=2y+2x=-2subtract the first from the second (y+2x)-(y+2x)=2-(-2)Simplify which turns out to be 0=4 which is not correct so the system has no solution.

y+2x=2y+2x=-2

The system

Substitution

Graphing

By Kosten Edwards

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