Module 1 Lesson 1.6 - Factoring Part 4: Distributive Property

Module 1

Factoring Part 4: Distributive Property

Objectives:

• Introduce Distributive Property

Lesson 6

Start

How do you compute these expressions:

Generally, compute inside PARENTHESIS () first! PEMDAS

Recall that a number OUTSIDE of parenthesis gets MULTIPLIED by anything inside parenthesis. Ways to show multiplication:

3(5) = 15

3(4 + 1) =

8(5) = 40

8(2 + 3) =

3 x 4 = 3 • 4 = 3(4) = (3)(4)

DistributivE Property

if a number is next to a set of numbers in parenthesis, you can distribute the number outside to each value inside using multiplication.

8(2 + 3) =

8(2) + 8(3) =

3(4) + 3(1) =

3(4 + 1) =

Practice:

You can use the distributive property

Which of the sums below can be expressed as 10(3 + 2)?

a) 13 + 12 b) 30 + 2 c) 3 + 20 d) 30 + 20

10(3) + 10(2) =

10(3 + 2) =

c) 23

a) 25

b) 32

d) 50

10(3 + 2) =

10(5) =

50

OR compute 10(3 + 2) and then see which answer to see which is the same!

Rewrite 15 + 25 using GCF and factoring.

Try computing and then see which answer to see which is the same!

15 + 25 =

a) 10(5 + 15) b) 5(10 + 20) c) 5(3 + 5) d) 15(1 + 10)