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Below is an example of a typical water treatment process used to create drinking water.

Relevant equationsFlow rate (Q) = velocity x areaArea of a circle = π r 2 = d 2 x 0.785KnownVelocity = 5 ft/secDiameter = 24 inches = 2 feetUnknowng/minQ = Velocity x AreaQ = 5 ft/sec x AreaA = 0.785 x 2ft2A = 3.14 ft2Q = Velocity x AreaQ = 5 ft/sec x 3.14 ft2Q = 15.7 ft3/secUnit conversion from ft3/sec to g/min