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24/25 EHE - Gradient & y = mx + c

thomas.payne

Created on March 20, 2024

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Transcript

Gradient & y=mx+c

y dπ‘₯

b2-4ac

A = lw

AS

Quizizz - 8Qs12

Pin: 2451 6324

Challenge

joinmyquiz.com

1. Convert 43/7 to a mixed fraction. 2. Convert 5 3/8 into an improper fraction. 3. Simplify 3π‘₯ + 7𝑦 - 6π‘₯ + 2𝑦 4. What is the value of the 5 in 0.35? 5. Angles in a quadrilateral add up to? 6. Write 60 as a product of its prime factors. 7. 33 8. π‘₯5 Γ— π‘₯7

y dπ‘₯

b2-4ac

A = lw

AS

Gradient

y dπ‘₯

b2-4ac

A = lw

AS

Gradient

Find the gradient of the line segment.

y dπ‘₯

b2-4ac

A = lw

AS

Gradient

y dπ‘₯

b2-4ac

A = lw

AS

Gradient

y dπ‘₯

b2-4ac

A = lw

AS

Gradient

Calculate the gradient of the line between each two points.

y dπ‘₯

b2-4ac

A = lw

AS

y = mx + c

y dπ‘₯

b2-4ac

A = lw

AS

y = mx + c

y dπ‘₯

b2-4ac

A = lw

AS

y = mx + c

y dπ‘₯

b2-4ac

A = lw

AS

y = mx + c

y dπ‘₯

b2-4ac

A = lw

AS

y = mx + c

Work out the equation of each line.

y dπ‘₯

b2-4ac

A = lw

AS

y = mx + c

Work out the equation of each line.

y dπ‘₯

b2-4ac

A = lw

AS

Gradient & y=mx+c

y dπ‘₯

Century Tasks

b2-4ac

Finding the Gradient of a Line Segment: Using the Graph [MF23.08]

01

A = lw

Finding the Gradient of a Line Segment: Using the Formula [MF23.09]

02

Head to 'my courses'
Click on this one
Then search for the nugget.

Finding y = mx + c from a Gradient and a Point [MF23.13]

03

AS

https://drive.google.com/file/d/1cw-5LkBKjywGEAnNUU7bDLDsUHd4x1ia/view?usp=sharing

Past paper questions

y dπ‘₯

b2-4ac

A = lw

AS

y dπ‘₯

b2-4ac

A = lw

AS

y dπ‘₯

b2-4ac

A = lw

AS

https://drive.google.com/file/d/1cw-5LkBKjywGEAnNUU7bDLDsUHd4x1ia/view?usp=sharing

y dπ‘₯

b2-4ac

A = lw

AS

https://drive.google.com/file/d/1cw-5LkBKjywGEAnNUU7bDLDsUHd4x1ia/view?usp=sharing

y dπ‘₯

b2-4ac

A = lw

AS

https://drive.google.com/file/d/1cw-5LkBKjywGEAnNUU7bDLDsUHd4x1ia/view?usp=sharing

A Level

Higher

Foundation

b2-4ac

dy

dx

f(π‘₯+a)

y dπ‘₯

Logs

A Level

Higher

Foundation

A Level

Higher

Foundation

A Level

Higher

Foundation

A Level

Higher

Foundation

A Level

Higher

Foundation

A Level

Higher

Foundation

b2-4ac

dy

dx

f(π‘₯+a)

y dπ‘₯

Logs

A Level

Higher

Foundation

A Level

Higher

Foundation

b2-4ac

dy

dx

f(π‘₯+a)

y dπ‘₯

Logs

b2-4ac

dy

dx

f(π‘₯+a)

y dπ‘₯

Logs

A Level

Higher

Foundation

b2-4ac

dy

dx

f(π‘₯+a)

y dπ‘₯

Logs

b2-4ac

dy

dx

f(π‘₯+a)

y dπ‘₯

Logs

b2-4ac

dy

dx

f(π‘₯+a)

y dπ‘₯

Logs

A Level

Higher

Foundation

A Level

Higher

Foundation

b2-4ac

dy

dx

f(π‘₯+a)

y dπ‘₯

Logs

b2-4ac

dy

dx

f(π‘₯+a)

y dπ‘₯

Logs

b2-4ac

dy

dx

f(π‘₯+a)

y dπ‘₯

Logs

b2-4ac

dy

dx

f(π‘₯+a)

y dπ‘₯

Logs

A Level

Higher

Foundation

b2-4ac

dy

dx

f(π‘₯+a)

y dπ‘₯

Logs

b2-4ac

dy

dx

f(π‘₯+a)

y dπ‘₯

Logs

b2-4ac

dy

dx

f(π‘₯+a)

y dπ‘₯

Logs

A Level

Higher

Foundation

A Level

Higher

Foundation

A Level

Higher

Foundation

b2-4ac

dy

dx

f(π‘₯+a)

y dπ‘₯

Logs

A Level

Higher

Foundation

A Level

Higher

Foundation

b2-4ac

dy

dx

f(π‘₯+a)

y dπ‘₯

Logs

b2-4ac

dy

dx

f(π‘₯+a)

y dπ‘₯

Logs

A Level

Higher

Foundation

b2-4ac

dy

dx

f(π‘₯+a)

y dπ‘₯

Logs

b2-4ac

dy

dx

f(π‘₯+a)

y dπ‘₯

Logs