CLIL ENGLISH PRESENTATION

CLIL:BODE PLOT

PRESENTATION

INTRODUCTION

Hendrick Wade Bode, an American engineer that invented the "Bode Plot", a method used to represent F(Jω).

WHAT IS THE BODE PLOT?

It describes the behaviour of the magnitude and phase of the transfer function of a system as ω varies.

This is the general representation of F(Jω) = Frequency response function

F(Jω)= [K * (Jω)^h* (1+ Jωτ1 )^n * (1- ω^2/ ω0^2+J2δ0 ω/ ω0)] / [ (Jω)^d * (1+ Jωτ2 )^m * (1- ω^2/ ω1^2+J2δ1 ω/ ω1)]

WHERE ARE THEY DRAWN?

They are drawn on a semi-logarithmic graphic. • On the x-axis there are the values of ω in powers of 10. • On the Y axis we have: 1) The module expressed in deciBel 2) The phase expressed in degrees or radiants.

some exercises

Let's consider some random values of K:

1) K=30 2) K=0,2 3) K=-15

Now we have to calculate the modules and the phases:

1) II dB II = 20log IKI = 20log I30I = 29,54dB ---> LK=0° 2) II dB II = 20log IKI = 20log I0,2I = 13,97dB ---> LK=0° 3) II dB II = 20log IKI = 20log I-15I = 23,52dB ---> LK=-180°

SOME TIPS TO SOLVE THIS EXERCISES

• When we solve the Module, we have to consider the absolute value of K, because the argument of a logarithm can't be zero or negative. • If the value of K >1, the result of the module will be always positive, while if the value of K is 0<K<1 the result of the module will be always negative. • For the phase, if K > 0, the phase is 0°. If K < 0, the phase is -180°

IT'S IMPORTANT TO CONSIDER THAT

Math lab and LabVIEW allow us to draw the bode plot and the true F(J ω) graph too

THANK YOU FOR WHATCHING!

Links of useful videos to comprehend the K function: • https://www.youtube.com/watch?v=LQH7oJJ Okmw • https://youtu.be/CYaRer4vsdo?si=Y_6vu7A- mRRzGUzv • https://youtu.be/CSAp9ooQRT0?si=zpvU_ajc AI5ubgln

Group: Bajraku, Cambi and Cecconi