Model real life situations using algebraic expressions

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Algebraic Expression

in real life situaiton

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QUESTION 1/6 - shows

Question 1/6 - SHOWS

Explanation

Let: J: Number of flowers John has (unknown) S: Number of flowers Sarah has We know: Sarah has twice as many flowers as John: S = 2J Together they have 30 flowers: J + S = 30 Expression for John's flowers (J): Substitute the first equation into the second equation: J + (2J) = 30

QUESTION 2/6 - geography

QUESTION 2/6 - geography

Explanation

Let: A: Cost of an adult ticket ($12) C: Cost of a child's ticket ($8) x: Number of children's tickets Expression for total cost: Cost of adult tickets: 3 * A = 36 Cost of children's tickets: x * C Total cost: 36 + (x * C) Therefore, the expression for the total cost is 36 + 8x.

QUESTION 5/6 - SPORTS

QUESTION 5/6 - sports

Explanation

Let: P: Cost of a pizza ($15) D: Cost of a drink ($3) y: Number of pizzas z: Number of drinks Expression for total cost: Cost of pizzas: y * P Cost of drinks: z * D Total cost: (y * P) + (z * D) Therefore, the expression for the total cost is 15y + 3z.

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