GROUP 8 MATHS PRESENTATION
QUESTION 1
evaluate the expressions using BODMAS
Evaluate the following expressions without using calculator.
7 + 3 × 4 − (2 − 10 ÷ 5 − (6 − 3))
7 + 3 × 4 − (2 − 10 ÷ 5 − 3) 7 + 3 × 4 − (2 − 2 − 3) 7 + 3 × 4 − ( -3) 22#
QUESTION 2
Solve for 𝑥 if 2𝑥 ÷ (7 + 2𝑥) = 2.
2𝑥 = 2 (7+2𝑥) 2𝑥 = 14 + 4𝑥 2𝑥 - 4𝑥 = 14 𝑥 = 14 - 2 𝑥 = -7 #
QUESTION 3
Given 𝑓(𝑥) = 3 ÷ (𝑥 − 1), find:
ii. 𝑥 if 𝑓(𝑥) = −4
i. 𝑓(7)3
-4𝑥 = 3 ÷ (𝑥 − 1)-4𝑥 = 3 - 4
3÷(7-1) =3÷(6) =0.5#
-4𝑥 = - 1 𝑥 = - 1
= 1
-4
QUESTION 4
Find the values of 𝑥 if 2𝑥
2 + 12𝑥 + 18 = 0.
2𝒳²+12𝒳+18=02(𝒳²+6𝒳+9) =0 2(𝒳 + 3)(𝒳+3) 𝒳=-3#
QUESTION 5
Given the formula 𝑆 = 𝑃(1 + 𝑖)
𝑛
, find the value of 𝑆 if 𝑃 = 2250, 𝑖 = 0.045, and
𝑛 = 12
S=P(1+i)n² S=P(2250)(1+i(0.045)n(12) S=3815.733
maths presentation
puteri
Created on November 19, 2023
Start designing with a free template
Discover more than 1500 professional designs like these:
View
Higher Education Presentation
View
Psychedelic Presentation
View
Harmony Higher Education Thesis
View
Vaporwave presentation
View
Geniaflix Presentation
View
Vintage Mosaic Presentation
View
Modern Zen Presentation
Explore all templates
Transcript
GROUP 8 MATHS PRESENTATION
QUESTION 1
evaluate the expressions using BODMAS
Evaluate the following expressions without using calculator.
7 + 3 × 4 − (2 − 10 ÷ 5 − (6 − 3))
7 + 3 × 4 − (2 − 10 ÷ 5 − 3) 7 + 3 × 4 − (2 − 2 − 3) 7 + 3 × 4 − ( -3) 22#
QUESTION 2
Solve for 𝑥 if 2𝑥 ÷ (7 + 2𝑥) = 2.
2𝑥 = 2 (7+2𝑥) 2𝑥 = 14 + 4𝑥 2𝑥 - 4𝑥 = 14 𝑥 = 14 - 2 𝑥 = -7 #
QUESTION 3
Given 𝑓(𝑥) = 3 ÷ (𝑥 − 1), find:
ii. 𝑥 if 𝑓(𝑥) = −4
i. 𝑓(7)3
-4𝑥 = 3 ÷ (𝑥 − 1)-4𝑥 = 3 - 4
3÷(7-1) =3÷(6) =0.5#
-4𝑥 = - 1 𝑥 = - 1
= 1
-4
QUESTION 4
Find the values of 𝑥 if 2𝑥 2 + 12𝑥 + 18 = 0.
2𝒳²+12𝒳+18=02(𝒳²+6𝒳+9) =0 2(𝒳 + 3)(𝒳+3) 𝒳=-3#
QUESTION 5
Given the formula 𝑆 = 𝑃(1 + 𝑖) 𝑛 , find the value of 𝑆 if 𝑃 = 2250, 𝑖 = 0.045, and 𝑛 = 12
S=P(1+i)n² S=P(2250)(1+i(0.045)n(12) S=3815.733