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24/25 EHE - Factorising
thomas.payne
Created on November 15, 2023
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Transcript
Factorising
y dπ₯
Spot the Mistakes
b2-4ac
A = lw
AS
Quizizz - 8Qs23
Pin: 2909 6608
Challenge
joinmyquiz.com
1. Probability of rolling a Prime on a dice?2. How many lines of symmetry does a square have? 3. A square has an area of 36cm2, what is its side length? 4. Simplify 5. Third square number minus fourth prime number 6. List the factors of 42 7. Chance of winning 0.3, drawing 0.1, losing ____? 8. What is 0.6 as a percentage?
y dπ₯
b2-4ac
A = lw
20z2
AS
Factorising
y dπ₯
b2-4ac
A = lw
AS
Factorising
1. 6π₯ + 42 2. 8π¦ - 32 3. 15π§ + 25 4. 10a - 20b 5. 12π₯ + 24π¦ 6. 21m - 7n 7. 3p + 15q 8. 14r - 21
1. aπ₯ + aπ¦ 2. bπ¦ - bπ§ 3. 2c + cπ¦ 4. dπ₯ + 5b 5. 2π₯ + 3π₯π¦ 6. fπ₯ - fπ§ 7. 5p + 7pq 8. 4π₯π¦ - 9π₯t
y dπ₯
b2-4ac
A = lw
AS
Factorising
y dπ₯
b2-4ac
A = lw
AS
Factorising
1. 3aπ₯ + 6aπ¦ 2. 4bπ₯ - 8bπ¦ 3. 5cπ₯ + 30c 4. 18dπ₯ - 6dπ¦ 5. 14eπ₯ + 21eπ¦ 6. 2fπ₯ + 10fπ¦ 7. 9gπ₯ - 18g 8. 8hπ₯ + 16hπ¦
y dπ₯
b2-4ac
A = lw
AS
Factorising
y dπ₯
b2-4ac
A = lw
AS
Factorising
y dπ₯
1. π₯2 + π₯ 2. π₯3 - π₯2 3. π¦3 + π¦2 4. π§2 - π§ 5. π₯4 - π₯2 6. 2π₯3 + 4π₯2 7. 3π¦3 - 6π¦2 8. 5π§2 + 10π§
b2-4ac
A = lw
AS
Factorising
y dπ₯
b2-4ac
A = lw
AS
Factorising Quadratics
y dπ₯
b2-4ac
A = lw
Factorise: π₯2 + 5π₯ + 6
AS
Factorising Quadratics
y dπ₯
Factorise: y2 + 10y + 21
b2-4ac
A = lw
AS
Factorising Quadratics
y dπ₯
1) π₯2 + 5π₯ + 6 2) π₯2 + 8π₯ + 15 3) y2 + 9y + 20 4) g2 + 6g + 5 5) π₯2 + 13π₯ + 42 6) π₯2 + 11π₯ + 24 7) b2 + 10b + 21 8) m2 + 11m + 18 9) d2 + 16d + 63 10) v2 + 15v + 36
b2-4ac
A = lw
AS
Factorising Quadratics
y dπ₯
Factorise: π₯2 + 2π₯ - 3
b2-4ac
A = lw
AS
Factorising Quadratics
y dπ₯
Factorise: b2 - 7b + 12
b2-4ac
A = lw
AS
Factorising Quadratics
y dπ₯
1) π₯2 - 11π₯ + 28 2) y2 - 9y + 18 3) f2 - 9f + 8 4) π₯2 + 3π₯ - 10 5) y2 + 3y - 4 6) π₯2 - π₯ - 12 7) z2 - 5z - 24 8) h2 - 7h - 18 9) π₯2 - 7π₯ + 12 10) y2 - 9y - 22
b2-4ac
A = lw
AS
Factorising
y dπ₯
Century Tasks
b2-4ac
Factorising into a Single Bracket 1: x Β± a or a Β± x [MF18.07]
01
A = lw
Factorising into a Single Bracket 2: ax Β± bx [MF18.08]
02
Factorising into a Single Bracket 3: axy(bxΒ² Β± cx Β± d) [MF18.09]
Head to 'my courses'
Click on this one
Then search for the nugget.
03
Factorising Quadratics 1: (x + a)(x + b) [MF18.15]
AS
04
Factorising Quadratics 2: (x Β± a)(x Β± b) [MF18.16]
05
https://drive.google.com/file/d/1cw-5LkBKjywGEAnNUU7bDLDsUHd4x1ia/view?usp=sharing
y dπ₯
b2-4ac
A = lw
AS
y dπ₯
b2-4ac
A = lw
AS
https://drive.google.com/file/d/1cw-5LkBKjywGEAnNUU7bDLDsUHd4x1ia/view?usp=sharing
y dπ₯
b2-4ac
A = lw
AS
https://drive.google.com/file/d/1cw-5LkBKjywGEAnNUU7bDLDsUHd4x1ia/view?usp=sharing
y dπ₯
b2-4ac
A = lw
AS
https://drive.google.com/file/d/1cw-5LkBKjywGEAnNUU7bDLDsUHd4x1ia/view?usp=sharing
b2-4ac
dy
dx
f(π₯+a)
y dπ₯
Logs
b2-4ac
dy
dx
f(π₯+a)
y dπ₯
Logs
b2-4ac
dy
dx
f(π₯+a)
y dπ₯
Logs
b2-4ac
dy
dx
f(π₯+a)
y dπ₯
Logs
b2-4ac
dy
dx
f(π₯+a)
y dπ₯
Logs
b2-4ac
dy
dx
f(π₯+a)
y dπ₯
Logs
A Level
Higher
Foundation
b2-4ac
dy
dx
f(π₯+a)
y dπ₯
Logs
A Level
Higher
Foundation
A Level
Higher
Foundation
b2-4ac
dy
dx
f(π₯+a)
y dπ₯
Logs
b2-4ac
dy
dx
f(π₯+a)
y dπ₯
Logs
A Level
Higher
Foundation
b2-4ac
dy
dx
f(π₯+a)
y dπ₯
Logs
b2-4ac
dy
dx
f(π₯+a)
y dπ₯
Logs
A Level
Higher
Foundation
A Level
Higher
Foundation
A Level
Higher
Foundation
A Level
Higher
Foundation
A Level
Higher
Foundation
A Level
Higher
Foundation
A Level
Higher
Foundation
b2-4ac
dy
dx
f(π₯+a)
y dπ₯
Logs
b2-4ac
dy
dx
f(π₯+a)
y dπ₯
Logs
b2-4ac
dy
dx
f(π₯+a)
y dπ₯
Logs
b2-4ac
dy
dx
f(π₯+a)
y dπ₯
Logs
b2-4ac
dy
dx
f(π₯+a)
y dπ₯
Logs
b2-4ac
dy
dx
f(π₯+a)
y dπ₯
Logs
A Level
Higher
Foundation
A Level
Higher
Foundation
A Level
Higher
Foundation
A Level
Higher
Foundation
b2-4ac
dy
dx
f(π₯+a)
y dπ₯
Logs
A Level
Higher
Foundation
A Level
Higher
Foundation
A Level
Higher
Foundation
b2-4ac
dy
dx
f(π₯+a)
y dπ₯
Logs
A Level
Higher
Foundation
A Level
Higher
Foundation