PRESENTATION
Creating a C Programming Platform for Accurate and Comprehensive Data Collection
INDEX
1. Group Name/ Member
2. Client" Organization Description
3. Problem/Goal
4. Proposed Solution
5. User
6. Input, Procees, Output
BSIT 1B - T147
tech Wizards
ubald joned l. tuquib
jan steven e. butaya
Jonard Noel Sanico
Documentation, Presentation
Lead programmer, Debugger
Flowchart, Documentation
Client:Barangay kisolon health center
Health centers are community-based and patient-directed organizations that provide affordable, accessible, high-quality primary health care services to individuals and families, including people experiencing homelessness, agricultural workers, residents of public housing, and veterans.
problem/ goal
Surveys that are conducted on paper, is impossible to monitor the specific inheritance of diseases. As a result, not all data is collected because occasionally, only those without paper are present.
SOLUTION
The team should create c programming platform survey that can be accessed on any digital device to gather complete and accurate information about specific inheritance of diseases, which will help understand and address health issues.
USER
People Of Barangay Kisolon that age 16 to 40 years old
PROCESS
INPUT
User ask to fill up the personal information about there name, address, age, birthday, and phone number. For the Survey we ask the user about inheritance diseases like Highblood, Cough, Fever, Cold, Asthma, Arthritis, Obesity, and Cancer. It input Y/N or y/n, Y means yes and N means No. If the user inputs invalid character for example '0' it will back the question.
PROCESS
do{if(highblood != 'Y' && highblood != 'y' && highblood != 'N' && highblood != 'n') while(highblood != 'Y' && highblood != 'y' && highblood != 'N' && highblood != 'n');
if(highblood == 'Y' || highblood == 'y') do{ if(cough != 'Y' && cough != 'y' && cough != 'N' && cough != 'n') while(cough != 'Y' && cough != 'y' && cough != 'N' && cough != 'n');
if(cough == 'Y' || cough == 'y'){ do{ if(fever != 'Y' && fever != 'y' && fever != 'N' && fever != 'n'){ while(fever != 'Y' && fever != 'y' && fever != 'N' && fever != 'n');
if(fever== 'Y' || fever == 'y'){ do{ if(cold != 'Y' && cold != 'y'&& cold != 'N' && cold != 'n'){ while(cold != 'Y' && cold != 'y' && cold != 'N' && cold != 'n');
if(cold == 'Y' || cold == 'y'){
PROCESS
do{ if(asthma != 'Y' && asthma != 'y' && asthma != 'N' && asthma != 'n'){ while(asthma != 'Y' && asthma != 'y' && asthma != 'N' && asthma != 'n');
if(asthma == 'Y' || asthma == 'y'){ do{ if(arthritis != 'Y' && arthritis != 'y' && arthritis != 'N' && arthritis != 'n'){ while(arthritis != 'Y' && arthritis != 'y' && arthritis != 'N' && arthritis != 'n');
if(arthritis == 'Y' || arthritis == 'y'){ do{ if(obesity != 'Y' && obesity != 'y' && obesity != 'N' && obesity != 'n'){ while(obesity != 'Y' && obesity != 'y' && obesity != 'N' && obesity != 'n');
if(obesity == 'Y' || obesity == 'y'){ do{ if(cancer != 'Y' && cancer != 'y' && cancer != 'N' && cancer != 'n'){ while(cancer != 'Y' && cancer != 'y' && cancer != 'N' && cancer != 'n');
if(cancer == 'Y' || cancer == 'y')
Output
Output
THANKS
COMPROG
Jansteben Butaya
Created on May 11, 2023
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Transcript
PRESENTATION
Creating a C Programming Platform for Accurate and Comprehensive Data Collection
INDEX
1. Group Name/ Member
2. Client" Organization Description
3. Problem/Goal
4. Proposed Solution
5. User
6. Input, Procees, Output
BSIT 1B - T147
tech Wizards
ubald joned l. tuquib
jan steven e. butaya
Jonard Noel Sanico
Documentation, Presentation
Lead programmer, Debugger
Flowchart, Documentation
Client:Barangay kisolon health center
Health centers are community-based and patient-directed organizations that provide affordable, accessible, high-quality primary health care services to individuals and families, including people experiencing homelessness, agricultural workers, residents of public housing, and veterans.
problem/ goal
Surveys that are conducted on paper, is impossible to monitor the specific inheritance of diseases. As a result, not all data is collected because occasionally, only those without paper are present.
SOLUTION
The team should create c programming platform survey that can be accessed on any digital device to gather complete and accurate information about specific inheritance of diseases, which will help understand and address health issues.
USER
People Of Barangay Kisolon that age 16 to 40 years old
PROCESS
INPUT
User ask to fill up the personal information about there name, address, age, birthday, and phone number. For the Survey we ask the user about inheritance diseases like Highblood, Cough, Fever, Cold, Asthma, Arthritis, Obesity, and Cancer. It input Y/N or y/n, Y means yes and N means No. If the user inputs invalid character for example '0' it will back the question.
PROCESS
do{if(highblood != 'Y' && highblood != 'y' && highblood != 'N' && highblood != 'n') while(highblood != 'Y' && highblood != 'y' && highblood != 'N' && highblood != 'n'); if(highblood == 'Y' || highblood == 'y') do{ if(cough != 'Y' && cough != 'y' && cough != 'N' && cough != 'n') while(cough != 'Y' && cough != 'y' && cough != 'N' && cough != 'n'); if(cough == 'Y' || cough == 'y'){ do{ if(fever != 'Y' && fever != 'y' && fever != 'N' && fever != 'n'){ while(fever != 'Y' && fever != 'y' && fever != 'N' && fever != 'n'); if(fever== 'Y' || fever == 'y'){ do{ if(cold != 'Y' && cold != 'y'&& cold != 'N' && cold != 'n'){ while(cold != 'Y' && cold != 'y' && cold != 'N' && cold != 'n'); if(cold == 'Y' || cold == 'y'){
PROCESS
do{ if(asthma != 'Y' && asthma != 'y' && asthma != 'N' && asthma != 'n'){ while(asthma != 'Y' && asthma != 'y' && asthma != 'N' && asthma != 'n'); if(asthma == 'Y' || asthma == 'y'){ do{ if(arthritis != 'Y' && arthritis != 'y' && arthritis != 'N' && arthritis != 'n'){ while(arthritis != 'Y' && arthritis != 'y' && arthritis != 'N' && arthritis != 'n'); if(arthritis == 'Y' || arthritis == 'y'){ do{ if(obesity != 'Y' && obesity != 'y' && obesity != 'N' && obesity != 'n'){ while(obesity != 'Y' && obesity != 'y' && obesity != 'N' && obesity != 'n'); if(obesity == 'Y' || obesity == 'y'){ do{ if(cancer != 'Y' && cancer != 'y' && cancer != 'N' && cancer != 'n'){ while(cancer != 'Y' && cancer != 'y' && cancer != 'N' && cancer != 'n'); if(cancer == 'Y' || cancer == 'y')
Output
Output
THANKS