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Mae M

composite functions

Unit 2 Discussion

Start!

what are composite funcitons?

Composite functions, like the name, are functions composing of other functions. These functions often take the form f[g(x)], read as "f of g of x". Since compostie functions invlove one function inside another, the process of multiplication can be used to simplify them. For example: f [ g (x) ] = ( f * g ) ( x )

Composite Function Example

Below is the simplified version of f [ g ( x ) ] when f (x) = 2x - 10 and g (x) = -4x -2 .

1. f [ g (x) ] = ( f * g ) (x)2. f [ g (x) ] = ( (2x - 10) * (-4x-2) ) 3. f [ g (x) ] = -8x + 4x + 40x + 20 4. f [ g (x) ] = 44x - 8x + 20 5. f [ g (x) ] = 36x + 20

KEY:green - composite function red - f ( x ) blue - g ( x )

1. Expand the composite function into its two defined parts2. Substitute f and g for the given functions 3. Multiply using FOIL (first, outer, inner, last) 4. Combine like terms 5. The end!

SInce all of these lines can be passed through by a vertical line with only one intersection, this means that both the original equations and their composite are functions!

Inverses of functions

Let's start with the same two functions from before, f ( x ) = 2x - 10 and g ( x ) = -4x -2, and find their inverse functions. Inverse functions - by definition - have the same ordered pairs as a function, but the coordinates are interchanged. An inverse function is modeled by f^-1 ( x ); read as "the inverse of f of x".

1. change g ( x ) to y 2. interchange x and y 3. isolate y 4. simplify

f ( x ) = 2x - 101. y = 2x - 10 2. x = 2y - 10 3. -2y = -x - 10 4. y = 0.5x + 5 5. f^-1 ( x ) = 0.5x + 5

g ( x ) = -4x - 21. y = -4x - 2 2. x = -4y - 2 3. 4y = -x - 2 4. y = -0.25x - 0.5 5. g^-1 ( x ) = -0.25x - 0.5 5. replace y with g^-1 ( x )

1. change f ( x ) to y 2. interchange x and y 3. isolate y 4. simplify 5. replace y with f^-1 ( x )

REMEMBER!The -1 in f^-1 ( x ) does NOT indicate an exponent, it simply just shows that it is an inverse.

g^-1 ( x ) = 0.25x - 0.5

Graphs of Inverses

f^-1 ( x ) = 0.5x + 5

IS A FUNCTION!

IS A FUNCTION!

To find the answer to this question, we can utilize the composite function f [g ( x )] from earlier: f [ g (x) ] = 36x + 20 when f ( x ) = 2x - 10 and g ( x ) = -4x - 2. Just like before with f^-1 ( x ) and g^-1 ( x ), we can use the same steps to find the inverse of the composite function f^-1 [ g (x) ]. 1. f [ g (x) ] = 36x + 20 1. original composite function 2. y = 36x + 20 2. replace f[g(x)] with y 3. x = 36y + 20 3. interchange x and y 4. -36y = -x + 20 4. isolate y 5. y = 1/36x - 5/9 5. simplify 6. f^-1 [ g (x) = 1/36x - 5/9 6. replace y with f^-1[g(x)] So, the inverse composite function of f ( x ) and g ( x ) is f^-1 [ g (x) = 1/36x = 5/9

Conclusion (part I)

If the inverses of two functions are both functions, will the inverse of the composite function made by the original functions also be a function?

Conclusion (part II)

f [ g (x) ] and f^-1 [ g (x) ]

f ( x ) and f^-1 ( x )

are functions!

both the composite and the inverse of the composite are functions; they both pass the vertical line test!

g ( x ) and g^-1 ( x )

are functions!

If the inverses of two functions are both functions, will the inverse of the composite function made by the original functions also be a function?

YES! With the example of the inverse, composite, and composite inverse of f ( x ) and g ( x ), it is proven that the inverse of the composite function made by the original functions is a function.

Thanks!