Quiz
circular permutations
Start
1/3
How many ways are there to seat 4 individuals around a circular table?
Option C 4! / 3! ways
Option B (4-1)! ways
Option A 4! ways
right answer
We arrange n objects around a circle in (n-1)! = n!/n ways Thus to arrange 4 individuals around a circle, we have (4-1)! ways
2/3
There are 10 colleagues sitting at a round table. There are 2 females and 8 males. How many ways are there to seat them such that the 2 females have to sit together?
Option C 2! x (8-1)!
Option B 2! x (10-1)!
Option A 2! x (9-1)!
right answer
(10 colleagues: 2 Females, 8 Males) Consider the 2 females as a single unit and arrange them within themselves: 2! ways Now arrange this female unit with the 8 males (total of 9 units) around the table: (9-1)! ways Thus number of ways to seat them such that the 2 females have to sit together: 2! x (9-1)! ways
3/3
A family of 6 with 4 adults and 2 children sits at a round dinner table. How many ways are there to sit them so that the 2 children are separated?
Option C 5! - (2! x3!)
Option B 5! - (2! x 4!)
Option A 2! x 4!
right answer
Consider number of ways to arrange the 6 members without restrictions: (6-1)! = 5! ways Consider when the 2 children are together as 1 unit then arrange this unit with the 4 other adults: 2! x (5-1)! = 2! x 4! ways Thus number of ways where 2 children are separated = 5! - (2! x 4!) (This is what we call the complementary method!) Think: Is there any alternative way to do this?
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Circular Permutations
3 RVHS STA LAM ZHAN HUI PEARL
Created on November 9, 2021
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Transcript
Quiz
circular permutations
Start
1/3
How many ways are there to seat 4 individuals around a circular table?
Option C 4! / 3! ways
Option B (4-1)! ways
Option A 4! ways
right answer
We arrange n objects around a circle in (n-1)! = n!/n ways Thus to arrange 4 individuals around a circle, we have (4-1)! ways
2/3
There are 10 colleagues sitting at a round table. There are 2 females and 8 males. How many ways are there to seat them such that the 2 females have to sit together?
Option C 2! x (8-1)!
Option B 2! x (10-1)!
Option A 2! x (9-1)!
right answer
(10 colleagues: 2 Females, 8 Males) Consider the 2 females as a single unit and arrange them within themselves: 2! ways Now arrange this female unit with the 8 males (total of 9 units) around the table: (9-1)! ways Thus number of ways to seat them such that the 2 females have to sit together: 2! x (9-1)! ways
3/3
A family of 6 with 4 adults and 2 children sits at a round dinner table. How many ways are there to sit them so that the 2 children are separated?
Option C 5! - (2! x3!)
Option B 5! - (2! x 4!)
Option A 2! x 4!
right answer
Consider number of ways to arrange the 6 members without restrictions: (6-1)! = 5! ways Consider when the 2 children are together as 1 unit then arrange this unit with the 4 other adults: 2! x (5-1)! = 2! x 4! ways Thus number of ways where 2 children are separated = 5! - (2! x 4!) (This is what we call the complementary method!) Think: Is there any alternative way to do this?
congrats
Try again!
wrong
Try again