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MATH PERFORMACE TASK

Janna Heart V. Casas

Created on October 26, 2021

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Transcript

PERFOMANCE TASK

Geometric Sequence

Group E

Module 6

Start

Objectives

  • Lesson
  • Introduction
  • Examples
  • Quiz
  • Ending

meet the group

Janna Heart Casas

Jhonna Mae Arsenio

Peachy Tamayo

  • Introduction
  • Lesson
  • formulas and how to use them
  • Examples
  • show the step by step solutions
  • Explain
  • Quiz
  • Closing
  • Editor

+ info

What is a Geometric Sequence?

Geometric Sequence

FINDING TERM/S OF Geometric Sequence

Geometric Sequence

Finding the sum of “n” terms of a geometric series.

*NOTE Finding 'r'. r = r2/r1

EXAMPLES

3.) Determine the geometric sequence in which the third term is 1⁄8 and the sixth term is 1⁄64.

2. ) Insert two geometric means between 3 and 192.

1. ) Find the geometric mean between 3 and 12. find m

+ info

+ info

+ info

solve no. 1

Solve

Final Answer

NEXT

solve no. 2

Solve

Final Answer

NEXT

solve no. 3

Solve

Final Answer

NEXT

shortquiz!!!

Start

clue:s = a1 ( 1 − rn/ 1 − r)

1/3

Find the sum of the first five terms of the geometric sequence (6, 18, 54, 162,...)

736

747

726

RIGHTANSWER

s = a(1−r^n/1−r) =6⋅(1−3^5/1−3) =6⋅(−242/−2) =6⋅121 =726

2/3

If the nth term is 128 and both the first term a and the common ratio r are 2. Can you calculate the total number of terms in the sequence?

clue: an=a⋅r^(n−1)

14

Right answer

an=a⋅r^(n−1) 128=2⋅2^(n−1) 64=2^(n−1) 2^6=2^(n−1) 6=n−1 n=7

3/3

clue:s = a1 ( 1 − rn/ 1 − r)

Find the sum of the infinite geometric series (64+32+16+8+…).

130

128

129

Right answer

r=32/64 =1/2 s=64/(1−1/2) =64/(1/2) =128

congrats

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Lesson learned!