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MATH PERFORMACE TASK
Janna Heart V. Casas
Created on October 26, 2021
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Transcript
PERFOMANCE TASK
Geometric Sequence
Group E
Module 6
Start
Objectives
- Lesson
- Introduction
- Examples
- Quiz
- Ending
meet the group
Janna Heart Casas
Jhonna Mae Arsenio
Peachy Tamayo
- Introduction
- Lesson
- formulas and how to use them
- Examples
- show the step by step solutions
- Explain
- Quiz
- Closing
- Editor
+ info
What is a Geometric Sequence?
Geometric Sequence
FINDING TERM/S OF Geometric Sequence
Geometric Sequence
Finding the sum of “n” terms of a geometric series.
*NOTE Finding 'r'. r = r2/r1
EXAMPLES
3.) Determine the geometric sequence in which the third term is 1⁄8 and the sixth term is 1⁄64.
2. ) Insert two geometric means between 3 and 192.
1. ) Find the geometric mean between 3 and 12. find m
+ info
+ info
+ info
solve no. 1
Solve
Final Answer
NEXT
solve no. 2
Solve
Final Answer
NEXT
solve no. 3
Solve
Final Answer
NEXT
shortquiz!!!
Start
clue:s = a1 ( 1 − rn/ 1 − r)
1/3
Find the sum of the first five terms of the geometric sequence (6, 18, 54, 162,...)
736
747
726
RIGHTANSWER
s = a(1−r^n/1−r) =6⋅(1−3^5/1−3) =6⋅(−242/−2) =6⋅121 =726
2/3
If the nth term is 128 and both the first term a and the common ratio r are 2. Can you calculate the total number of terms in the sequence?
clue: an=a⋅r^(n−1)
14
Right answer
an=a⋅r^(n−1) 128=2⋅2^(n−1) 64=2^(n−1) 2^6=2^(n−1) 6=n−1 n=7
3/3
clue:s = a1 ( 1 − rn/ 1 − r)
Find the sum of the infinite geometric series (64+32+16+8+…).
130
128
129
Right answer
r=32/64 =1/2 s=64/(1−1/2) =64/(1/2) =128
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