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FLIPPED CLASSROOM GENIAL PRESENTATION

Gilven Rey Celocia

Created on March 4, 2021

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Transcript

Performance Task in

Statistics and Probability

Submitted by: Maryjo Valerie Celocia(Grade 11-HUMSS 1)

START

You are a satistician. You are assigned to gather data about the habits of atleast 30 teenager students. Using the data you have gathered, you are going to analyze the distribution of the given data and construct a normal curve.

Part of your task is to prepare a report containing the following details:

  • Data from at least 30 teenagers about number of hours per weel spent
  • In front of computer or gadgets
  • Playing physical sports or exercising
  • Sleeping
  • Studying

RAW DATA OF THE 30 TEENAGERS' SURVEY

https://docs.google.com/forms/d/16xVgmv2OIQA08hXiVzbr5y94gWzanwn7xOUBeG9FDfM/edit#responses

SURVEY:

10-20 per hour

23-35 per hour

40-50 per hour

23+35= 58

40+50= 90

10+20= 30

58/2= 29

30/2= 15

90/2= 45

45

29

15

=IN FRONT OF COMPUTER OR GADGETS

RAW DATA OF THE 30 TEENAGERS' SURVEY

15 15 15 15 15 15 15 15 15 15 15 15 15 15 15 15 15 15 15 15 15 15 15 15 15 15 29 45 45

=IN FRONT OF COMPUTER OR GADGETS

UNGROUPED FREQUENCY DISTRIBUTION TABLE

= IN FRONT OF A COMPUTER OR GADGETS

Mean:

Standard Deviation

Highest Data Value: 45

Lowest Data Value: 15

Mean: 18.47

Standard Deviation: 8.78

34.13%

34.13%

13.59%

13.59%

2.15%

2.15%

If the mean for the 30 teenagers' number of hours per week spents in front of computer or gadgets is approximately 18.47 hours with a standard deviation approximately equal to 8.78 hours, one possible interpretation is "49.87 of the teenagers spend approximately 18.47 to 44.79 hours in front of computer or gadgets in a week"

= PHYSICAL SPORTS OR EXERCISING

RAW DATA OF THE 30 TEENAGERS' SURVEY

15 15 15 15 15 15 15 15 15 15 15 15 15 15 15 15 15 15 15 15 15 15 29 29 29 29 29 29 29 29 29 45

= PHYSICAL SPORTS OR EXERCISING

UNGROUPED FREQUENCY DISTRIBUTION TABLE

= PHYSICAL SPORTS OR EXERCISING

Mean:

Standard Deviation

Highest Data Value: 45

Lowest Data Value: 15

Mean= 19.27 Standard Deviation= 7.71

34.13%

34.13%

13.59%

13.59%

2.15%

2.15%

If the mean for the 30 teenagers' number of hours per week spents in physical sports or exercising is approximately 19.27 hours with a standard deviation approximately equal to 7.71 hours, one possible interpretation is " 49.87% of the teenagers spend approximately 19.27 to 42.4 hours in physical sports or exercising in a week"

= SLEEPING

RAW DATA OF THE 30 TEENAGERS' SURVEY

15 15 15 15 15 15 15 15 15 15 15 29 29 29 29 29 29 29 29 29 29 29 45 45 45 45 45 45 45 45

= SLEEPING

UNGROUPED FREQUENCY DISTRIBUTION TABLE

= SLEEPING

Mean:

Standard Deviation

Highest Data Value: 45Lowest Data Value: 15

Mean= 28.13 Standard Deviation= 9.20

34.13%

34.13%

13.59%

13.59%

2.15%

2.15%

If the mean for the 30 teenagers' number of hours per week spents in sleeping is approximately 28.13 hours with a standard deviation approximately equal to 9.20 hours, one possible interpretation is "68.26% of the teenagers spend approximately 28.18 to 37.33 hours in sleeping in a week"

= STUDYING

RAW DATA OF THE 30 TEENAGERS' SURVEY

15 15 15 15 15 15 15 15 15 15 15 15 15 15 15 15 15 15 15 15 15 15 29 29 29 29 29 29 45 45

= STUDYING

UNGROUPED FREQUENCY DISTRIBUTION TABLE

= STUDYING

Mean:

Standard Deviation

Highest Data Value: 45 Lowest Data Value: 15

Mean= 19.47 Standard Deviation= 7.94

34.13%.

34.13%

13.59%

13.59%

2.15%

2.15%

If the mean for the 30 teenagers' number of hours per week spents in studying is approximately 19.47 hours with a standard deviation approximately equal to 7.94 hours, one possible interpretation is "49.87% of the teenagers spend approximately 19.47 to 43.29 hours in studying in a week"

Thank you!

Submitted to: Ms. Marianne Joy B. Dagaraga Teacher in Statistics and Probability