The Shopping Habit_Statistic Class

PANNASASTRA UNIVERSITY OF CAMBODIA

Sub: Introduction to Statistic & Its Application

Prof: Moolio Pahlaj

Midterm Project

The Shopping Habit

Of Phnom Penh Citizen

CONTENT

Introduction

Methodology

Online Shopping

Physical Shopping

Analysis

Conclusion

Introduction

Make a right decision

Time Consuming

Price Negtiation

Physical Shopping

Online Shopping

Convenvient

Just One Click

Methodology

• The Purpose
• The Date collects thru online Survey "Google Survey"
• 56 Respondents with 21 questions

Link

Link

Physical Shopping

• n=56 • Range = (Maximum-Minimum)/Value time And we decide to set value time= 4 • Range = (6-0) / 4= 1.5

How many time do you usually do Physical Shopping?

Physical Shopping

- Less than -0.5 00- Less than 0.5 05- Less than 1.5 35 - Less than 2.5 39 - Less than 3.5 44 - Less than 4.5 45 - Less than 5.5 50 - Less than 6.5 56

Physical Shopping

Physical Shopping

Subtitle

Physical Shopping

Subtitle

Physical Shopping

Physical Shopping

Physical Shopping

Physical Shopping

• Mean Mean = ∑x/n , (n=56) ∑ 𝑥 = 0+0+0+0+0+0+0+0+0+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+ 1+1+1+1+1+1+1+1+1+1+1+1+2+2+2+2+2+2+2+2+2+3+3+3+3+3+3+4+5+6 = 80 Mean = 𝑥̅= ( 80)/56 = 1.42 ≅ 1.4

Physical Shopping

Median

Median = (1+1)/2 = 1

Mode

Mode=1

Physical Shopping

• Mid-Range

Mid-Range = 6 +0/2= 3

• Variance𝑠 2= n(∑ x )-(∑ x) /(n(n-1)) , (n = 50) ∑ 𝑥=80, (∑ 𝑥) = 6400 Σ𝑥 = (0)2+ (0)2 + (0)2+ (0)2+ (0)2+ (0)2+ (0)2+ (0)2+ (0)2+ (1)2+ (1)2 + (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (2)2+ (2)2+ (2)2+ (2)2+ (2)2+ (2)2+(2)2+ (2)2+ (2)2+ (3)2 +(3)2+ (3)2+ (3)2+ (3)2+ (3)2 +(4)2+ (5)2+ (6)2= 196 => 𝑠 =

56(196)-6400 56(56-1)

= 1.48 ≅ 1.5

Physical Shopping

Standard Deviation S = √𝑠 = √1.5= 1.22

Find z-score (Standard Score) for the first data value of your key quantitative variable you collected Z-score = x = (x-x)/S =(0-6)/1.22 = - 4.91

Physical Shopping

Data:

MD= Q1= 1 MD = Q2 = 1 MD= Q3= 2 IQR= Q3-Q1= 2-1= 1 Q1-1.5 (IQR) = 1-1.5(1) = -0.5 Q3+1.5(IQR) = 2+1.5(1) = 3.5 So 4, 5, 6 are greater than Q3+1.5(IQR) = 3.5 Therefore4, 5, 6 are an outlier.

Physical Shopping

The reason why people like Physical Shopping

Based on the result above, we can analysis that the reason people prefer to do physical online because of different choices which can let us more convenient to choose a right one. As well as the quality, we can make sure the quality is acceptable and suit within our expectation.

Online Shopping

How many time do you usually do Online Shopping?

• n= 56 • Range = (Maximum-Minimum)/Value Time • And we decide to set value time= 4 • Range = (6-0) / 4= 1.5

Online Shopping

Less than -0.5 00 Less than 0.5 09 Less than 1.5 38 Less than 2.5 47 Less than 3.5 53 Less than 4.5 54 Less than 5.5 55 Less than 6.5 56

Online Shopping

Online Shopping

Online Shopping

Online Shopping

Online Shopping

Online Shopping

• Mean Mean = ∑ , (n=50) Mean = 𝑥̅ =( 118)/56 = 2.1

∑ 𝑥 = 0+0+0+0+0+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+2+2+2+2+3+3+3+3+3+4+5+5+5+5+5+6+6+6+6+6+6 = 118

Online Shopping

•Median

Median = (1+1)/2 = 1

• Mode

Mode=1

Online Shopping

• Mid-Range

Mid-Range = 6 +0/2= 3

𝑠 = n(∑ x )-(∑ x ) /(n(n-1)) , (n = 50) ∑ 𝑥 =118, (∑ 𝑥) = 13924 Σ𝑥 = (0)2+ (0)2 + (0)2+ (0)2+ (0)2+ (1)2 + (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+ (1)2+(1)2+ (1)2+ (1)2+ (1)2+ (2)2+ (2)2+ (2)2+ (2)2+ (3)2+ (3)2+ (3)2+ (3)2+(3)2+ (4)2+ (5)2+ (5)2 +(5)2+ (5)2 +(5)2+ (6)2+ (6)2 +(6)2+ (6)2+ (6)2+ (6)2= 448 56(448)-13924

• Variance

=> 𝑠 =

= 3.6

56(56-1)

Online Shopping

• Standard Deviation S = √𝑠 = √3.6 = 1.89 ≅ 2

. Find z-score

Z-score = x=(x - x)/S = (1-6)/2 = -2.5

Online Shopping

. Check the Data Set for Outliers

MD= Q2= 1 MD= Q1 = 1 MD= Q3 = 3 IQR = Q3 - Q1 = 3-1= 2 Q1 - 1.5 (IQR) = 1 -1.5(2) = -2 Q3 +1.5 (IQR) = 1 +1.5(2) = 4 So 5, 6 are greater than Q3 +1.5 (IQR) = 4 Therefore, 5, 6 are an outliers.

Analysis & Conclusion

According to the statistic survey amount 56 respondents who live in Phnom Penh, the result shows that there are 40 respondents who prefer online shopping more than physical shopping. Most of the citizen that chose online shopping usually shopping 1 time per week. For physical shopping, there are 16 respondents who like to do physical shopping. They mostly do physical shopping 1 time per week. In conclusion, we can see that the amount of people who like doing online shopping is largest more than physical shopping because online shopping are convenient, afforadable and save time more than physical shopping.